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(2x+1)(x-4)=x^-4x-6
We move all terms to the left:
(2x+1)(x-4)-(x^-4x-6)=0
We get rid of parentheses
(2x+1)(x-4)-x^+4x+6=0
We multiply parentheses ..
(+2x^2-8x+x-4)-x^+4x+6=0
We add all the numbers together, and all the variables
(+2x^2-8x+x-4)+3x+6=0
We get rid of parentheses
2x^2-8x+x+3x-4+6=0
We add all the numbers together, and all the variables
2x^2-4x+2=0
a = 2; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·2·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{4}{4}=1$
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